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Autor:hawe
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Beispiel Helix Pfad

Beispiel Helix Pfad
Z=60, C=(30,30,0), w(t):=C+ 30 (t cos(10 t ), t sin(10 t ), t)
Z=40, C=(30,30,20), D=(-40, -20, 35), w(t):=C + t (D-C) Z=40, C = (30, 30, 0), w(t):=C+ 30 (cos(6 t ), sin(6 t ), t) Z=60, C=(30,30,0), w(t):=C+ 30 (t cos(10 t ), t sin(10 t ), t)

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