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Diagonalization

Diagonalization

Given an n x n matrix and let for any column vector in (in standard coordinates). Sometimes we can simplify the matrix representation of drastically if we choose a "nice" coordinate system. For example, if there are n linearly independent eigenvectors of , then they can form a basis for , which is called the eigenbasis of . Using it to define a new coordinate system, the new matrix representation of T will be , where i.e. is an eigenvector corresponding to the eigenvalue for . In other words, , where i.e. the matrix formed by the column vectors of the eigenvectors (in standard coordinates). Hence, is similar to the diagonal matrix and this process is called diagonalization. A matrix is said to be diagonalizable if it is similar to a diagonal matrix. The following theorem gives a characterization of diagonalizable matrices: Theorem: An n x n matrix is diagonalizable if and only if has n linearly independent eigenvectors. Example 1: Recall the previous example . We have already known that is an eigenvector of corresponding to and is an eigenvector of corresponding to . Therefore, we define and , where . In other words, (Note: the matrix in the diagonalization is not unique as there are many choices of eigenvectors.) Example 2: The matrx is not diagonalizable because its only eigenvalue is and the eigenspace is , which is not enough to form a basis for . Example 3: Diagonalize , if possible. Solution: Compute the eigenvalues by solving the characteristic equation: Hence, the eigenvalues of are . When , solve . The matrix is row reduced to the matrix in echelon form : The solutions in the parametric vector form are . When , solve . The matrix is row reduced to the matrix in echelon form : The solutions in the parametric vector form are . We have three eigenvectors that are linearly independent. Therefore, they form an eignebasis for and is diagonalizable: (Note: The eigenvalues in the diagonal matrix must be in the same order as the eigenvectors in .)

Exercise

Diagonalize , if possible.