Google Classroom
GeoGebraClasse GeoGebra

From Archytas' simple triangle to Archytas' solution (I)

This interactive diagram shows a simple way to obtain Archytas' solution from Archytas' triangle, i.e. given , , to find two mean proportionals of , starting with Archytas' triangle with AM = and ΑΔ = (shown in the figure). Selecting K with the left button of the mouse, and moving it around the circumference, you can achieve Archytas' solution, when I and I' coincide. To clean the canvas and get the initial configuration displayed, click on the button with two circular arrows in the right upper corner of the canvas.