Jumping Right In
Let's get started. Plotted below is the function
f(x)=x^2+2x, which is the same function we were studying last chapter. I've gone ahead and constructed a secant line by way of a "nudging" variable h. I've also set h to 0.01.
Therefore, the slope of the line g at the point A matches the function f at the point A very closely.
Without resorting to using a limit (see last Chapter), this is about as good as we can match f at point A.
Type this code into the input bar to keep track of the slope of g at point A :
(x(A),slope(g))Move ahead to check that you did it correctly, and to continue the discussion.