Lagrange Multipliers ● Example 7
Extremizing f(x, y)=exp(-x² - 2y²) (x² + 3y²) with the constraint condition: g(x,y):=x⁴ + 2y⁶ + x y - 0.8 = 0 . CAS and ggB solutions are compared. The critical points of the corresponding Lagrangian, its global maximum and minimum are determined.
![Image](https://www.geogebra.org/resource/aac3u4pt/LVjwgJPlk1gZgqfi/material-aac3u4pt.png)
![Image](https://www.geogebra.org/resource/ryn9dzqu/q6060IVmqAdRhtnx/material-ryn9dzqu.png)
![Curve of Intersection of two surfaces: f (x, y) and g(x,y).](https://www.geogebra.org/resource/edvmvvep/xsyLym11BzFFgiIU/material-edvmvvep.png)