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Borsuk Problem in 2 Dimensions (Latter Trial)
Autor:
beryakuru
∠KBI = ∠KBJ = 30°. K = (B + I + J)/3. Therefore, BI = BJ = IJ.
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Tanzanian Ngoma - Model 2
Square Cross Sections
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Solving 2x2 and 3x3 Systems Using Cramer's Rule
Tanzanian Ngoma - Model 3
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Mapping 4
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Quadratic graph transformations
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